WebbTranscribed Image Text: The pressure 70.0 m under water is 788 kPa. What is this pressure in atmospheres (atm)? P = atm What is this pressure in millimeters of mercury … WebbType in your own numbers in the form to convert the units! Quick conversion chart of mm Hg to kPa 1 mm Hg to kPa = 0.13332 kPa 5 mm Hg to kPa = 0.66661 kPa 10 mm Hg to kPa = 1.33322 kPa 20 mm Hg to kPa = 2.66645 kPa 30 mm Hg to kPa = 3.99967 kPa 40 mm Hg to kPa = 5.3329 kPa 50 mm Hg to kPa = 6.66612 kPa 75 mm Hg to kPa = …

The pressure 75.0 meters under water is 837 kPa. What is this …

WebbThe pressure 85.0 m under water is 935 kPa. What is the pressure in atm and what is the pressure in mmHg? The pressure 75.0 meters under water is 837 kPa. What is this … WebbA: The pressure is measured to be 886 kPa at a depth of 80.0 m under water. Q: 3. A gas sample has a pressure of 583 mmHg and a volume of 3.75 L. If it is compressed to 1.05 L,… A: (3) According to Boyle's Law: P1V1=P2V2 where, P1 = Initial Pressure = 583 mmHg V1 = Initial Volume… grant thornton iselin

Answered: 5. The pressure of a certain valley… bartleby

Webb25 mars 2024 · Calculate the pH of a buffer solution prepared by mixing 0.010 moles of acetic acid (CH3COOH; pKa = 4.8) with 0.040 mol potassium acetate (CH3COOK) in water to give 2L of solution b) To the solution in 1 answer Na2S (aq) + Cu (NO3)2 (aq) + NaNO3 (aq) + CuS (8) Express your answer as a chemical equation. Idehtify all of the phases in … WebbMultiply the answer (which is in atm) by 760.0 mmHg atm¯1to get mmHg Problem #13:Calculate the volume 3.00 moles of a gas will occupy at 24.0 °C and 762.4 mm Hg. Solution: Rearrange the Ideal Gas Law to this: V = nRT / P Substitute values into the equation: V = [(3.00 mol) (0.08206 L atm mol¯1K¯1) (297.0 K)] / (762.4 mmHg / 760.0 … WebbExpert Answer Solution: (a) (i) 1 kPa = 0.00987 atm => 837 kPa = 837 * 0.00987 atm => 837 kPa = 8.26119 atm => Required value of P is 8.261 atm. (ii) 1 Pa = 0.00750062 mm of Hg … grant thornton irvine